Experiment 3 (Day 3): Growth Table Calculations

Since the equation have been simplified from to {Log [A / (A0) ] },

Log ( X / X0) = {Log [ A / (A0) ] }

Therefore, to calculate Log ( X / X0) it is being replaced with {Log [ A / (A0) ] }.



For sample 1, absorbance is 0.431 while A0 is 0.308

{Log [ A / (A0) ] } = {Log [ 0.431 / (0.308) ] }
= 0.146

For sample 2, absorbance is 0.397 while A0 is 0.308

{Log [ A / (A0) ] } = {Log [ 0.387 / (0.308) ] }
= 0.099

For sample 3, absorbance is 0.408 while A0 is 0.308

{Log [ A / (A0) ] } = {Log [ 0.408 / (0.308) ] }
= 0.122

For sample 4, absorbance is 0.477 while A0 is 0.308

{Log [ A / (A0) ] } = {Log [ 0.477 / (0.308) ] }
= 0.162

For sample 5, absorbance is 0.483 while A0 is 0.308

{Log [ A / (A0) ] } = {Log [ 0.483 / (0.308) ] }
= 0.195

For sample 6, absorbance is 0.427 while A0 is 0.308

{Log [ A / (A0) ] } = {Log [ 0.427 / (0.308) ] }
= 0.142

For sample 7, absorbance is 0.410 while A0 is 0.308

{Log [ A / (A0) ] } = {Log [ 0.410 / (0.308) ] }
= 0.124

For sample 8, absorbance is 0.507 while A0 is 0.308

{Log [ A / (A0) ] } = {Log [ 0.507 / (0.308) ] }
= 0.216

For sample 9, absorbance is 0.526 while A0 is 0.308

{Log [ A / (A0) ] } = {Log [ 0.526 / (0.308) ] }
= 0.232

For sample 10, absorbance is 0.532 while A0 is 0.308

{Log [ A / (A0) ] } = {Log [ 0.532 / (0.308) ] }
= 0.237